3/x^2-4/x+6=0

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Solution for 3/x^2-4/x+6=0 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

3/(x^2)-(4/x)+6 = 0

3/(x^2)-4*x^-1+6 = 0

3*x^-2-4*x^-1+6 = 0

t_1 = x^-1

3*t_1^2-4*t_1^1+6 = 0

3*t_1^2-4*t_1+6 = 0

DELTA = (-4)^2-(3*4*6)

DELTA = -56

DELTA < 0

x belongs to the empty set

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